Dear Ranjith,
> Hi all,
> The function of this script is used to print the
> aleurier_access.log (apache log file) file content exactly.
[snip]
> What i like to do is
> How to print individual set values?
> for eg,
> If I want to print the %h (remote host id) set values alone?
> I want to sort %h set values?
> Repeated host id to printed only once and also other unique host
> ids values and store %h values in a database?
I don't know if I understood your requirement/query correctly.
Assuming that you want to parse access_log file such that for every
host entry in the access_log, you want to group corresponding fields
together as a set of records, the code could be something like
below:
# --------------8<---------------------------------8<---------------
require 'rubygems'
require 'apachelogregex'
require 'pp'
format = '%h %l %u %t \"%r\" %>s %b \"%{Referer}i\" \"%{User-Agent}i\"'
parser = ApacheLogRegex.new(format)
access_log = Hash.new
# Creating a hash of an array of hashes!
# Can be simplified based on your actual requirement.
File.readlines('aleurier_access.log').collect do |line|
record = parser.parse(line)
# The code below does the actual job. Can be a one-liner
# if you know ternary operators or maybe if expression.
if access_log.key? record["%h"]
access_log[record["%h"]] << record
else
access_log[record["%h"]] = Array.new
end
end
# Now let's test some!
puts access_log.keys
while true
print "Enter ip address: "
ipaddr = gets.chomp
puts "-" * 40
pp access_log[ipaddr]
puts "-" * 40
end
# --------------8<---------------------------------8<---------------
Is this what you wanted ?
--
Chandrashekar Babu.,
http://www.chandrashekar.info/
http://www.slashprog..com/
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