On Apr 29, Håvard Wahl Kongsgård <haavard.kongsga...@gmail.com> wrote:
> How do I get the year from search_movie() list (without calling > ia.update)? > I know that for movieID it is > for i in ia.search_movie("matrix"): > print i.movieID When you need to retrieve an information, a Movie (or Person, Company and Character) instance behaves as a Python dictionary. That is: movie['title'] movie['year'] Beware that some information may be missing (usually not 'title' - and 'year' is present _most_ of the times), and so a better idea would be to use movie.get('year'), which returns None if 'year' is not a known keyword. In your case you don't need to call the 'update' method, since the year is one of the few information gathered calling 'search_movie'. Notice that the 'movieID' is not a key but an attribute of the Movie instance, because it's not an information about the movie, but something we need to identify it (other "contextual" information are attributes, too). For other information, feel free to ask or check the documentation: http://imdbpy.sourceforge.net/?page=docs Bye, -- Davide Alberani <davide.alber...@gmail.com> [GPG KeyID: 0x465BFD47] http://www.mimante.net/ ------------------------------------------------------------------------------ _______________________________________________ Imdbpy-help mailing list Imdbpy-help@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/imdbpy-help