David Carson writes:
> 
> I'm sure there is some complication involved, but it is apparently
> possible.  The "cvs rdiff -r<revA> -r<revB>" syntax handles this
> problem correctly, going from <revA> to <revB> even if from trunk to
> branch.  As long as point A is an ancestor of point B, then there is
> only one way to get to B from A.

But rdiff doesn't care whether A is an ancestor of B or not, it compares
*any* two revisions.  The complication is determining whether A is an
ancestor of B, B is an ancestor of A, or neither is an ancestor of the
other.

-Larry Jones

My dreams are getting way too literal. -- Calvin

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