David Carson writes: > > I'm sure there is some complication involved, but it is apparently > possible. The "cvs rdiff -r<revA> -r<revB>" syntax handles this > problem correctly, going from <revA> to <revB> even if from trunk to > branch. As long as point A is an ancestor of point B, then there is > only one way to get to B from A.
But rdiff doesn't care whether A is an ancestor of B or not, it compares *any* two revisions. The complication is determining whether A is an ancestor of B, B is an ancestor of A, or neither is an ancestor of the other. -Larry Jones My dreams are getting way too literal. -- Calvin _______________________________________________ Info-cvs mailing list [EMAIL PROTECTED] http://mail.gnu.org/mailman/listinfo/info-cvs