В Sun, 11 Jan 2015 15:12:10 +0100
Amadeusz Żołnowski <[email protected]> пишет:
> ---
> lsinitrd.sh | 6 +++---
> 1 file changed, 3 insertions(+), 3 deletions(-)
>
> diff --git a/lsinitrd.sh b/lsinitrd.sh
> index 4f12c2c..dc1f88f 100755
> --- a/lsinitrd.sh
> +++ b/lsinitrd.sh
> @@ -124,7 +124,7 @@ extract_files()
> list_modules()
> {
> echo "dracut modules:"
> - $CAT "$image" | cpio --extract --verbose --quiet --to-stdout --
> 'lib/dracut/modules.txt' 'usr/lib/dracut/modules.txt' 2>/dev/null
> + $CAT "$image" | cpio --extract --verbose --quiet --to-stdout --
> 'lib64/dracut/modules.txt' 'lib/dracut/modules.txt'
> 'usr/lib/dracut/modules.txt' 2>/dev/null
How it can become lib64? Name is really hardcoded
./dracut.sh: printf "%s\n" "$i" >> $initdir/lib/dracut/modules.txt
> ((ret+=$?))
> }
>
> @@ -217,7 +217,7 @@ ret=0
> if (( ${#filenames[@]} > 0 )); then
> extract_files
> else
> - version=$($CAT "$image" | cpio --extract --verbose --quiet --to-stdout
> -- 'lib/dracut/dracut-*' 'usr/lib/dracut/dracut-*' 2>/dev/null)
> + version=$($CAT "$image" | cpio --extract --verbose --quiet --to-stdout
> -- 'lib64/dracut/dracut-*' 'lib/dracut/dracut-*' 'usr/lib/dracut/dracut-*'
> 2>/dev/null)
Can it really be lib64 here?
> ((ret+=$?))
> echo "Version: $version"
> echo
> @@ -226,7 +226,7 @@ else
> echo
> "========================================================================"
> else
> echo -n "Arguments: "
> - $CAT "$image" | cpio --extract --verbose --quiet --to-stdout --
> 'lib/dracut/build-parameter.txt' 'usr/lib/dracut/build-parameter.txt'
> 2>/dev/null
> + $CAT "$image" | cpio --extract --verbose --quiet --to-stdout --
> 'lib64/dracut/build-parameter.txt' 'lib/dracut/build-parameter.txt'
> 'usr/lib/dracut/build-parameter.txt' 2>/dev/null
Ditto.
> echo
> list_modules
> list_files
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