On 5/3/2015 7:40 PM, Xuxiaohu wrote: >> We're talking about IP-in-IP, IP-in-UDP-in-IP, IP-in-GRE-in-IP, etc. In all >> cases, you >> > have: >> > >> > N inside N+header > > Assume N is equal to 8000, since the max size of the original IP > packet is 1500, isn't it (i.e., 8000-1500) large enough to hold > additional encapsulation headers?
That depends on how many encapsulation headers there are. Yes, it's somewhat absurd to expect 6500 bytes of additional header, so that will probably fit. But that's not the case with IPv6 in IPv6; the largest payload is 1240, but the MTU is 1280. Joe _______________________________________________ Int-area mailing list [email protected] https://www.ietf.org/mailman/listinfo/int-area
