On Sat, 30 Aug 2003 [EMAIL PROTECTED] wrote:
> Since the inner loop declares $i again, it should mask the outer loop's
> $i as per other languages. Besides being useful, it makes more sense.
No, that's not true. You don't redeclare ANYTHING here... you're just
using the same variable $i, just like you would do in C.
> Otherwise, the declaratory statement in the second loop is completely
> meaningless.
You don't declare anything...
Derick
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