On Feb 22, 2004, at 5:15 PM, Derick Rethans wrote:
On Sun, 22 Feb 2004 [EMAIL PROTECTED] wrote:
It's generating an idivl, which gives you an exception if the (signed) result is too large (a.k.a. integer overflow).
Did you notice your compiler warning "this decimal constant is unsigned
only in ISO C90"? ;)
Yes I did
+2147483648 is: 10000000 00000000 00000000 00000000. -2147483648 is too large to be represented by a signed integer (as it would be ~(+2147483648) + 1,
No, -2147483648 is the lower bound and 2147483647 is the upper bound for
signed integers.
-2147483648 = 10000000000000000000000000000000 2147483647 = 01111111111111111111111111111111
it still doesn't explain the FPE here. What does explain it is that -2147483648 / -1 = 2147483648 which is too large.
Doesn't the rval in modulus need to be unsigned?
Then you are effective doing
-2147483648 % 2147482647
which is 2147483648.
No?
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