Hi,
Karoly Negyesi a écrit :
> > Please note that the only difference between f1 and f2 that the first
> > records the return value of f3() into a variable. However, this
> > changes the output:
> >
> > array(1) {
> > ["foo"]=>
> > &string(3) "bar"
> > }
> > array(1) {
> > ["foo"]=>
> > string(3) "bar"
> > }
> >
> > Is this a bug? Or I miss something?
>
When copying an array containing a reference, the reference is keeped. :
$value = 'foo';
$array = array (&$value);
$array2 = $array;
$array2[0] = 'bar';
echo $array[0]; // bar
Here, the &string(3) means that it's referenced. Indeed, $throwaway
contains a reference to it.
change your f1 to this :
function f1() {
global $a;
$array = array();
$throwaway = f3($array);
unset($throwaway);
var_dump($a);
}
And the "&" will obviously disappear, as the reference no longer exists.
Kind regards
-- Etienne Kneuss http://www.colder.ch/ [EMAIL PROTECTED]
--
Etienne Kneuss
http://www.colder.ch/
[EMAIL PROTECTED]
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