Etienne Kneuss wrote:
Hello,
On Mon, Mar 1, 2010 at 1:33 PM, mathieu.suen <mathieu.s...@easyflirt.com> wrote:
Hi,
I am proposing a comparison between PHP closure with lisp one.
First thing to compare is how scope are capture:
Suppose I want to create a function that add.
The common idiom to do it in lisp is:
(defun adder (x) #'(lambda (y) (+ x y)))
Then if I want the add3 method you can do:
(setf (symbol-function 'add3) (adder 3))
(add3 4) => 7
Now let reproduce that in php:
$adder = function ($x) {return function ($y) use($x) {return $y + $x;};};
$add3 = $adder(3);
echo $add3(4); => 7
Every thing is fine but let change the adder into a counter :
In lisp you could do:
(let ((sum 0))
(defun counter () (setf sum (1+ sum))))
(counter) => 1
(counter) => 2
(counter) => 3 ...
In other to have the same behavior in PHP you first need to transform the
let into a lambda which make no difference in lisp:
(funcall #'(lambda (sum) (defun counter () (setf sum (1+ sum)))) 0)
Now we are ready to do it in PHP.
$createCounter = function ($sum) { return function () use ($sum) {return
++$sum;};};
$counter = $createCounter(0);
$counter(); => 1
$counter(); => 1
$counter(); => 1
...
So that's not the expected behavior.
In oder to have the expected behavior you need to add & in front of $sum.
But & is kind of evil since it mimics dynamic scoping:
$array = array(1, 2, 3);
foreach($array as $pos)
{
$adders[] = function ($x) use (&$pos) { return $pos+ $x;};
}
foreach($adders as $addIt)
{
echo $addIt(5);
}
use($var) will import by copy, so you won't have the behavior you
expect. If you want to keep a value in a function between calls, you
can use "static $sum = 0;".
You call it import by copy. I would rather say a mix-up of concept
between value and variable.
Thanks for your attention
-- Mathieu Suen
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-- Mathieu Suen
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