$var = $arr['key'] ?? : 'empty';
Also note this is possible with the recent proposal Hannes and I were discussing. It simply looks like $var = $arr?['key'] ?: 'empty'; The ?[ avoids notices and the ?: works as it always has. Ben. -- PHP Internals - PHP Runtime Development Mailing List To unsubscribe, visit: http://www.php.net/unsub.php
