On 2021-07-08 14:57, Kai-Heng Feng wrote:
On Thu, Jul 8, 2021 at 6:18 PM Robin Murphy <robin.mur...@arm.com> wrote:
On 2021-07-08 10:28, Joerg Roedel wrote:
On Thu, Jul 08, 2021 at 03:42:32PM +0800, Kai-Heng Feng wrote:
@@ -344,6 +344,9 @@ static int iommu_init_device(struct device *dev)
iommu = amd_iommu_rlookup_table[dev_data->devid];
dev_data->iommu_v2 = iommu->is_iommu_v2;
+
+ if (dev_data->iommu_v2)
+ swiotlb = 1;
This looks like the big hammer, as it will affect all other systems
where the AMD GPUs are in their own group.
What is needed here is an explicit check whether a non-iommu-v2 device
is direct-mapped because it shares a group with the GPU, and only enable
swiotlb in this case.
Right, it's basically about whether any DMA-limited device might at any
time end up in an IOMMU_DOMAIN_IDENTITY domain. And given the
possibility of device hotplug and the user being silly with the sysfs
interface, I don't think we can categorically determine that at boot time.
Also note that Intel systems are likely to be similarly affected (in
fact intel-iommu doesn't even have the iommu_default_passthough() check
so it's probably even easier to blow up).
swiotlb is enabled by pci_swiotlb_detect_4gb() and intel-iommu doesn't
disable it.
Oh, right... I did say I found this dance hard to follow. Clearly I
shouldn't have trusted what I thought I remembered from looking at it
yesterday :)
Also not helped by the fact that it sets iommu_detected which *does*
disable SWIOTLB, but only on IA-64.
I wonder if we can take the same approach in amd-iommu?
Certainly if there's a precedent for leaving SWIOTLB enabled even if it
*might* be redundant, that seems like the easiest option (it's what we
do on arm64 too, but then we have system topologies where some devices
may not be behind IOMMUs even when others are). More fun would be to try
to bring it up at the first sign of IOMMU_DOMAIN_IDENTITY if it was
disabled previously, but I don't have the highest hope of that being
practical.
Robin.
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