So I tried dropping this in the ul/li format with the CSS and I still
end up with it just drawing the buttons on top of each other it
appears. I only see the ++ button being visible.
What I'm trying to achieve is:
Row Label
[--] [ - ] [ + ] [++]
Where the buttons are side by side on the same row. Any help is
greatly appreciated!
Thanks
Scott
On Apr 3, 11:27 am, Remi Grumeau <[email protected]> wrote:
> Using a ul/li combinaison?
>
> <div class="row">
> <ul class="inlinebuttons">
> <li><a id="backButton" class="button" href="#"></a></li>
> <li><a class="button blueButton" href="#">--</a></li>
> <li><a class="button blueButton" href="#">-</a></li>
> <li><a class="button blueButton" href="#">+</a></li>
> <li><a class="button blueButton" href="#">++</a></li>
> </ul>
> </div>
>
> then with some CSS
> ul.inlinebuttons {
> width: 100%;}
>
> ul.inlinebuttons li {
> display: inline;
>
> }
>
> But where do you want those buttons to be? In the page or in the toolbar? i
> see backButton... you know you can only have one element with the same ID ?
>
> Remi
>
>
>
> On Tue, Apr 3, 2012 at 8:11 PM, sblair <[email protected]> wrote:
> > I'm trying to figure out how to create multiple small buttons within a
> > single row all side by side.
>
> > Basicallly I'm looking to have 4 buttons ( --, -, +, ++ ) in a
> > single row in IUI.
>
> > I've tried doing this as these buttons are the perfect size, but it
> > just ignored the row I was putting them at and put them in the first
> > row at the top with them all piled on top of each other and not
> > positioned next to each other.
>
> > <div class="row>
> > <a id="backButton" class="button" href="#"></a>
> > <a class="button blueButton" href="#">--</a>
> > <a id="backButton" class="button" href="#"></a>
> > <a class="button blueButton" href="#">-</a>
> > <a id="backButton" class="button" href="#"></a>
> > <a class="button blueButton" href="#">+</a>
> > <a id="backButton" class="button" href="#"></a>
> > <a class="button blueButton" href="#">++</a>
> > </div>
>
> > Suggestions?
>
> > Thanks.
> > Scott
>
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