Window size limits the amount of responses that the responder has to remember.

After receiving requests 17, 18 and 19, the responder needs to remember those 
three responses, because if it gets a retransmission, it should reply with the 
old response.

When request #20 arrives, it is safe to discard #17.  If it was still valid for 
the initiator to send request #17 again, the responder would have to retain all 
the old responses indefinitely.

________________________________
From: Amjad Inamdar (amjads) [mailto:amj...@cisco.com]
Sent: Wednesday, July 22, 2009 12:23 PM
To: Yoav Nir; Raj Singh
Cc: ipsec@ietf.org
Subject: RE: [IPsec] [IKEv2] Questions on windowing in IKEv2

Hi Yoav,

Any benefits of this behaviour over allowing 'window-size' outstanding requests 
at any given time.

Thanks,
-Amjad

________________________________
From: ipsec-boun...@ietf.org [mailto:ipsec-boun...@ietf.org] On Behalf Of Yoav 
Nir
Sent: Wednesday, July 22, 2009 2:34 PM
To: 'Raj Singh'
Cc: ipsec@ietf.org
Subject: Re: [IPsec] [IKEv2] Questions on windowing in IKEv2
No. All the draft says, is that to send 20, you need to have received answers 
to everything up to and including 17. You don't get to always have three 
outstanding requests.

________________________________
From: Raj Singh [mailto:rsjen...@gmail.com]
Sent: Wednesday, July 22, 2009 11:57 AM
To: Yoav Nir
Cc: ipsec@ietf.org
Subject: Re: [IPsec] [IKEv2] Questions on windowing in IKEv2

Hi Yoav,

Do you think this behavior contradicts with definition of windowing mentioned 
in draft that if responder window is 3, initiator can have 3 outstanding 
request ?

Regards,
Raj
On Wed, Jul 22, 2009 at 1:09 PM, Yoav Nir 
<y...@checkpoint.com<mailto:y...@checkpoint.com>> wrote:

Hi Raj.



Too many variables, let's assume values without loss of generality.



Suppose N=3, and you have send requests 17, 18 and 19. Because of the network 
problems, you got responses for 18 and 19, but not *yet* for 17.



What the draft (and RFC 4306) says, is that you keep retransmitting 17, until 
you get a response.  Before that, you can't begin transmitting #20. If your 
retransmissions of #17 time out (after "at least a dozen retransmissions over 
at least 2 minutes") then you assume that the peer has died, and silently 
discard the IKE SA.  This will usually not happen in the above scenario, 
because once the network is back, the responder will also reply to #17.



Hope this helps



________________________________

From: ipsec-boun...@ietf.org<mailto:ipsec-boun...@ietf.org> 
[mailto:ipsec-boun...@ietf.org<mailto:ipsec-boun...@ietf.org>] On Behalf Of Raj 
Singh
Sent: Wednesday, July 22, 2009 8:52 AM
To: ipsec@ietf.org<mailto:ipsec@ietf.org>
Subject: [IPsec] [IKEv2] Questions on windowing in IKEv2



Hi Group,

According to IKEv2bis-04, section 2.3

-----------------------------------------

   An IKE endpoint MUST NOT exceed the peer's stated window size for












   transmitted IKE requests.  In other words, if the responder stated
























   its window size is N, then when the initiator needs to make a request












   X, it MUST wait until it has received responses to all requests up












   through request X-N.  An IKE endpoint MUST keep a copy of (or be able
























   to regenerate exactly) each request it has sent until it receives the












   corresponding response.  An IKE endpoint MUST keep a copy of (or be












   able to regenerate exactly) the number of previous responses equal to
























   its declared window size in case its response was lost and the












   initiator requests its retransmission by retransmitting the request.
























----------------------------
























Now, suppose responder window size is N.
























Initiator send a request (X-N) but Initiator does get












response for request no (X-N) say due to n/w flapping.












So initiator schedules this request for re-transmissions












but between the time intervals of re-transmission n/w comes UP
























and request no. (X-N+1) to (X) goes fine i.e. these request get response.












Now, initiator wants to make another request i.e. request no.












(X+1). But according to draft it can't make that request as it has












not received the response for request no (X-N) even though there is
























only one outstanding request in transit.
























Also draft says:












---------------------------












 The SET_WINDOW_SIZE notification asserts that the sending endpoint is












   capable of keeping state for multiple outstanding exchanges,
























   permitting the recipient to send multiple requests before getting a












   response to the first.












------------------------
























That means windowing is for outstanding request.












So in above mentioned scenario even though there is only 1
























outstanding request and window size is N but we are not able to send












next request because of windowing definition.
























Maybe i am missing something here.












Please elaborate the on the behavior in above scenario.




































Regards,












Raj


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