westonpace opened a new issue, #14898: URL: https://github.com/apache/arrow/issues/14898
### Describe the enhancement requested This method would return a table with one column for each key and one row for each unique combination of keys. This can actually be done today by passing in an empty list of aggregates, and the result should be identical, however this is not obvious behavior to the user: ``` >>> tab = pa.Table.from_pydict({"x": [1, 2, 3, 1, 2, 3], "y": ["a", "b", "c", "c", "b", "a"]}) >>> tab.group_by(["x", "y"]).aggregate([]) pyarrow.Table x: int64 y: string ---- x: [[1,2,3,1,3]] y: [["a","b","c","c","a"]] ``` ### Component(s) Python -- This is an automated message from the Apache Git Service. To respond to the message, please log on to GitHub and use the URL above to go to the specific comment. To unsubscribe, e-mail: issues-unsubscr...@arrow.apache.org.apache.org For queries about this service, please contact Infrastructure at: us...@infra.apache.org