westonpace opened a new issue, #14898:
URL: https://github.com/apache/arrow/issues/14898

   ### Describe the enhancement requested
   
   This method would return a table with one column for each key and one row 
for each unique combination of keys.  This can actually be done today by 
passing in an empty list of aggregates, and the result should be identical, 
however this is not obvious behavior to the user:
   
   ```
   >>> tab = pa.Table.from_pydict({"x": [1, 2, 3, 1, 2, 3], "y": ["a", "b", 
"c", "c", "b", "a"]})
   >>> tab.group_by(["x", "y"]).aggregate([])
   pyarrow.Table
   x: int64
   y: string
   ----
   x: [[1,2,3,1,3]]
   y: [["a","b","c","c","a"]]
   ```
   
   ### Component(s)
   
   Python


-- 
This is an automated message from the Apache Git Service.
To respond to the message, please log on to GitHub and use the
URL above to go to the specific comment.

To unsubscribe, e-mail: issues-unsubscr...@arrow.apache.org.apache.org

For queries about this service, please contact Infrastructure at:
us...@infra.apache.org

Reply via email to