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https://issues.apache.org/jira/browse/CALCITE-5894?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=17753862#comment-17753862
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JingDas commented on CALCITE-5894:
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[~jhyde] I re-read this part of the paper again. I aggre with you, after “order 
homogenization”, interesting order can be push down. If the interesting order 
is above join, after push down,this give a chance to use `

EnumerableMergeJoin` instead of `EnumerableHashJoin` in the optimize because 
one input of join is sorted. In another scene after “order homogenization” sort 
maybe removed, which can not happen without “order homogenization”. I will log 
a new Jira case for “order homogenization”.

> Add SortRemoveRedundantRule to remove redundant sort fields if they are 
> functionally dependent on other sort fields
> -------------------------------------------------------------------------------------------------------------------
>
>                 Key: CALCITE-5894
>                 URL: https://issues.apache.org/jira/browse/CALCITE-5894
>             Project: Calcite
>          Issue Type: New Feature
>            Reporter: JingDas
>            Assignee: JingDas
>            Priority: Minor
>              Labels: pull-request-available
>
> In some scene, Sort fields can be reduct, if sort fields contain unique key
> For example
> {code:java}
> SELECT ename, salary FROM Emp
> order by empno, ename{code}
> where `empno` is a key,  `ename` is redundant since `empno` alone is 
> sufficient to determine the order of any two records.
> So the SQL can be optimized as following:
> {code:java}
> SELECT name, Emp.salary FROM Emp
> order by empno{code}
> For another example:
> {code:java}
> SELECT e_agg.c, e_agg.ename
> FROM
> (SELECT count(*) as c, ename, job FROM Emp GROUP BY ename, job) AS e_agg
> ORDER BY e_agg.ename, e_agg.job, e_agg.c {code}
> Although `e_agg.ename` is not a key but field `ename` is unique and not null, 
> it can be optimized as following:
> {code:java}
> SELECT e_agg.c, e_agg.ename
> FROM (SELECT count(*) as c, ename, job FROM Emp GROUP BY ename, job) AS e_agg
> ORDER BY e_agg.ename, e_agg.job{code}
> Sorting is an expensive operation, however. Therefore, it is imperative that 
> sorting
> is optimized to avoid unnecessary sort field.
>  



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