zentol closed pull request #6647: [hotfix][docs] Fix error html tag in batch 
index documentatition
URL: https://github.com/apache/flink/pull/6647
 
 
   

This is a PR merged from a forked repository.
As GitHub hides the original diff on merge, it is displayed below for
the sake of provenance:

As this is a foreign pull request (from a fork), the diff is supplied
below (as it won't show otherwise due to GitHub magic):

diff --git a/docs/dev/batch/index.md b/docs/dev/batch/index.md
index c624fce8954..62e41174c1b 100644
--- a/docs/dev/batch/index.md
+++ b/docs/dev/batch/index.md
@@ -592,7 +592,7 @@ val output: DataSet[(Int, String, Double)] = 
input.sum(0).min(2)
       </td>
     </tr>
 
-    </tr>
+    <tr>
       <td><strong>Join</strong></td>
       <td>
         Joins two data sets by creating all pairs of elements that are equal 
on their keys.
@@ -608,7 +608,7 @@ val result = input1.join(input2).where(0).equalTo(1)
         describe whether the join happens through partitioning or 
broadcasting, and whether it uses
         a sort-based or a hash-based algorithm. Please refer to the
         <a 
href="dataset_transformations.html#join-algorithm-hints">Transformations 
Guide</a> for
-        a list of possible hints and an example.</br>
+        a list of possible hints and an example.<br />
         If no hint is specified, the system will try to make an estimate of 
the input sizes and
         pick the best strategy according to those estimates.
 {% highlight scala %}
@@ -700,7 +700,6 @@ val result = in.partitionByRange(0).mapPartition { ... }
 {% endhighlight %}
       </td>
     </tr>
-    </tr>
     <tr>
       <td><strong>Custom Partitioning</strong></td>
       <td>


 

----------------------------------------------------------------
This is an automated message from the Apache Git Service.
To respond to the message, please log on GitHub and use the
URL above to go to the specific comment.
 
For queries about this service, please contact Infrastructure at:
us...@infra.apache.org


With regards,
Apache Git Services

Reply via email to