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https://issues.apache.org/jira/browse/FLINK-1221?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=14209510#comment-14209510
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ASF GitHub Bot commented on FLINK-1221:
---------------------------------------
Github user rmetzger commented on the pull request:
https://github.com/apache/incubator-flink/pull/197#issuecomment-62861050
Thank you for the feedback.
I've updated the pull request. I also checked what happens if the code has
been compiled without debug symbols `-g:none`. This leads to stacks like this:
```
e = java.lang.Thread.getStackTrace(Thread.java:1552)
e = Test.a(Unknown Source)
e = Test.main(Unknown Source)
```
I think its fine to have it this way.
@uce: Getting call location of a transformation inside the operator would
be difficult for operators that have different depths of calls (I think the
Reduce operator for example is being called from different locations with
different stack sizes). Therefore, it is much easier to get the location name
as early as possible
> Use program source line of invocation as the default function name
> -------------------------------------------------------------------
>
> Key: FLINK-1221
> URL: https://issues.apache.org/jira/browse/FLINK-1221
> Project: Flink
> Issue Type: Improvement
> Components: Java API, Scala API
> Affects Versions: 0.8-incubating
> Reporter: Stephan Ewen
> Assignee: Robert Metzger
> Priority: Minor
> Fix For: 0.8-incubating
>
>
> Right now, the default function name is {{getClass().getName()}}.
> In many cases, this is not really very revealing. Using line in the source
> code where the function is invoked is more helpful.
> This can be easily obtained by
> {code}
> Thread.getCurrentThread().getStackTrace()[0]
> {code}
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