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https://issues.apache.org/jira/browse/HIVE-12778?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=17201521#comment-17201521
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Jiehong Lian commented on HIVE-12778:
-------------------------------------
It's a bug when the having clause contains the aggregator with distinct hint,
while the aggregator does not in the select clause. such as:
{code:java}
// code placeholder
SELECT key
FROM src
GROUP BY key
HAVING COUNT(value) >= 4 and count(distinct value) > 1
;{code}
I have a patch fix the bug.
> Having with count distinct doesn't work for special combination
> ---------------------------------------------------------------
>
> Key: HIVE-12778
> URL: https://issues.apache.org/jira/browse/HIVE-12778
> Project: Hive
> Issue Type: Bug
> Components: Hive
> Affects Versions: 1.1.0, 1.2.1
> Reporter: Peter Brejcak
> Priority: Major
>
> There is problem for combination of count(distinct ) in having clause without
> count(distinct ) in select clause.
> First case returns error *FAILED: SemanticException [Error 10002]: Line
> Invalid column reference* (unexpected)
> If I add count(distinct ) to select clause result is ok (expected).
> Please run code to see it.
> Steps to reproduce:
> {code}
> create table table_subquery_having_problem (id int, value int);
> insert into table table_subquery_having_problem values (1,1);
> insert into table table_subquery_having_problem values (1,2);
> insert into table table_subquery_having_problem values (1,3);
> insert into table table_subquery_having_problem values (1,4);
> insert into table table_subquery_having_problem values (1,5);
> insert into table table_subquery_having_problem values (1,6);
> insert into table table_subquery_having_problem values (1,7);
> insert into table table_subquery_having_problem values (1,8);
> insert into table table_subquery_having_problem values (1,9);
> select x.id from table_subquery_having_problem x
> group by x.id
> having count(distinct x.value)>1; -- result is ERROR
> select x.id, count(distinct x.value) from table_subquery_having_problem x
> group by x.id
> having count(distinct x.value)>1; --result is OK
> {code}
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