Irina Truong created SPARK-21096:
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Summary: Pickle error when passing a member variable to Spark
executors
Key: SPARK-21096
URL: https://issues.apache.org/jira/browse/SPARK-21096
Project: Spark
Issue Type: Bug
Components: Spark Core
Affects Versions: 2.1.1
Reporter: Irina Truong
There is a pickle error when submitting a spark job that references a member
variable in a lambda, even when the member variable is a simple type that
should be serializable.
Here is a minimal example:
https://gist.github.com/j-bennet/8390c6d9a81854696f1a9b42a4ea8278
In the gist above, this method will throw an exception:
{{ def build_fail(self):
processed = self.rdd.map(lambda row: process_row(row, self.multiplier))
return processed.collect()
}}
While this method will run just fine:
{{ def build_ok(self):
mult = self.multiplier
processed = self.rdd.map(lambda row: process_row(row, mult))
return processed.collect()
}}
In this example, {{self.multiplier}} is just an int. However, passing it into a
lambda throws a pickle error, because it is trying to pickle the whole
{{self}}, and that contains {{sc}}.
If this is the expected behavior, then why should re-assigning
{{self.multiplier}} to a variable make a difference?
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