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https://issues.apache.org/jira/browse/SPARK-24571?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel
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Maxim Gekk updated SPARK-24571:
-------------------------------
Description:
Currently, Spark doesn't support literals with the Char (java.lang.Character)
type. For example, the following code throws an exception:
{code}
val df = Seq("Amsterdam", "San Francisco", "London").toDF("city")
df.where($"city".contains('o')).show(false)
{code}
It fails with the exception:
{code:java}
Unsupported literal type class java.lang.Character o
java.lang.RuntimeException: Unsupported literal type class java.lang.Character o
at org.apache.spark.sql.catalyst.expressions.Literal$.apply(literals.scala:78)
{code}
One of the possible solutions can be automatic conversion of Char literal to
String literal of length 1.
was:
Currently, Spark doesn't support literals with the Char (java.lang.Character)
type. For example, the following code throws an exception:
{code:scala}
val df = Seq("Amsterdam", "San Francisco", "London").toDF("city")
df.where($"city".contains('o')).show(false)
{code}
It fails with the exception:
{code}
Unsupported literal type class java.lang.Character o
java.lang.RuntimeException: Unsupported literal type class java.lang.Character p
at org.apache.spark.sql.catalyst.expressions.Literal$.apply(literals.scala:78)
{code}
One of the possible solutions can be automatic conversion of Char literal to
String literal of length 1.
> Support literals with values of the Char type
> ---------------------------------------------
>
> Key: SPARK-24571
> URL: https://issues.apache.org/jira/browse/SPARK-24571
> Project: Spark
> Issue Type: Improvement
> Components: SQL
> Affects Versions: 2.3.1
> Reporter: Maxim Gekk
> Priority: Minor
>
> Currently, Spark doesn't support literals with the Char (java.lang.Character)
> type. For example, the following code throws an exception:
> {code}
> val df = Seq("Amsterdam", "San Francisco", "London").toDF("city")
> df.where($"city".contains('o')).show(false)
> {code}
> It fails with the exception:
> {code:java}
> Unsupported literal type class java.lang.Character o
> java.lang.RuntimeException: Unsupported literal type class
> java.lang.Character o
> at org.apache.spark.sql.catalyst.expressions.Literal$.apply(literals.scala:78)
> {code}
> One of the possible solutions can be automatic conversion of Char literal to
> String literal of length 1.
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