If the form is dynamic it won't work. If the form is static there are
some cases where the actual name of the field is an attribute and it
won't work either (it will some day when I have the time and patience to
fix it). You'll have to post a link to the pdf if you're interested in
an answer.
Paulo
> -----Original Message-----
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On
> Behalf Of Ismael F
> Sent: Wednesday, December 12, 2007 8:39 AM
> To: Post all your questions about iText here
> Subject: [iText-questions] AcroForm setField error due to XFA
> entry - bug orcorrect behavoiur?
>
> Hello,
>
> I have read that XFA is not supported with iText in different
> iText questions:
> http://www.nabble.com/extent-of-XFA-support-in-itext-t3336804.html
> http://www.junlu.com/msg/162152.html
> http://www.mail-archive.com/[EMAIL PROTECTED]
> net/msg34432.html
> http://itext.ugent.be/library/question.php?id=30
> http://groups.google.com/group/comp.text.pdf/browse_thread/thr
> ead/aef69adde8ba9512
> ...
> ...
>
> but I found an error related to it and I don't know if it's a
> bug or the correct behaviour.
>
> An extract form a XFA pdf stream after data filled with
> Acrobat Professional 8.0, and to be managed with iText 2.0:
>
> <?xml version="1.0" encoding="UTF-8"?>
> <?xfa generator="XFA2_4" APIVersion="2.5.6290.0"?>
> <xdp:xdp xmlns:xdp="http://ns.adobe.com/xdp/";>
> ...
> ...
>
> with the second line (xfa node) the code below fails in
> XfaForm class at XfaForm(PdfReader reader):
> ...
> ...
> domDocument = db.parse(new
> ByteArrayInputStream(bout.toByteArray()));
> Node n = domDocument.getFirstChild();
> n = n.getFirstChild(); // this is null ...
> // "n" is null as a consequence "templateNode" and
> "templateSom" also will be null.
> // Then when setting Acroform fields by "setField"
> will throw an exception
> while (n != null) {
> ...
> ...
>
> Perhaps this could be solutionated with the next line instead
> of the previous one (n = n.getFirstChild();):
> while (n!=null && !"xdp".equals( n.getLocalName()) )
> n = n.getNextSibling();
>
> but, It was a bug?
>
> Thanks,
>
> Ismael
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