1) OK
2) No. During a IupDestroy, one of the other handles in the array could be
destroyed, so the check must remain.
Best,
Scuri
Em sáb., 11 de jul. de 2020 às 00:31, Ranier Vilela <ranier_...@hotmail.com>
escreveu:
> De: Antonio Scuri <antonio.sc...@gmail.com>
> Enviado: sexta-feira, 29 de maio de 2020 13:12
> Para: IUP discussion list.
> Assunto: Re: [Iup-users] IUP iupDlgListDestroyAll refactored
>
> > Because IupDestroy will also remove the dialog from that list and
> list->next will be invalid.
> Like this, it worked without problems.
>
> void iupDlgListDestroyAll(void)
> {
> int i, count = 0;
> Ihandle** ih_array = (Ihandle**)malloc(idlg_count * sizeof(Ihandle*));
> Idiallst *list;
> for (list = idlglist; list; list = list->next)
> {
> if (iupObjectCheck(list->ih))
> {
> ih_array[count] = list->ih;
> ++count;
> }
> }
>
> for (i = 0; i < count; ++i)
> {
> IupDestroy(ih_array[i]); /* this will also destroy the list */
> }
>
> free(ih_array);
> }
>
> Advantagens:
> 1. Avoid assign variable count with i value;
> 2. Avoid call iupObjectCheck for every ih_array[i], since they have all
> been verified.
>
> regards,
> Ranier Vilela
>
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> Iup-users@lists.sourceforge.net
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