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JRE.exe IS NOT the right file to execute! you MUST use java.exe! the jre is
simply the jdk without compiler, just the runtime envirionment. most
probably you'll find the jre in a own directory and there is a second
java.exe
michael
-----Original Message-----
From: Don Pierce [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, August 09, 2000 5:23 PM
To: Java-Apache-Users
Subject: jdk versus jre
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WHEN YOU POST, include all relevant version numbers, log files,
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My config is on NT4
Apache 1.3.13
JServ 1.1.1
JDK1.1.8
I want to move to jre for my production environment
and did the following in my jserv.properties:
I changed this line
wrapper.bin=c:\jdk1.1.8\bin\java.exe
to this line
wrapper.bin=c:\jdk1.1.8\bin\jre.exe
Now when I start Apache i get this in the Apache error.log:
Class not found: org.apache.jserv.JServ
Everything was working just fine before the change so I
do not understand why jre cannot find the class anymore?
FYI here is my classpath wrapper entries:
wrapper.classpath=d:\apache jserv\ApacheJServ.jar
wrapper.classpath=d:\jsdk2.0\lib\jsdk.jar
wrapper.classpath=D:\JTurbo4-20\JTurbo.jar
Don
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