Hi, All.
Here is the sequence of java access levels:
public->protected->default->private
As public is the strongest so child's method can only be public. And
it can throw only IOException or its subclasses or nothing at all.
import java.io.IOException;
class Farther{
public void FarthersMethod() throws IOException {
throw new IOException();
}
}
class Son extends Farther{
public void FarthersMethod() throws IOException {
}
}
The following is wrong:
class Son extends Farther{
private void FarthersMethod() throws IOException {
}
}
class Son extends Farther{
public void FarthersMethod() throws Exception {
}
}
On Oct 18, 8:38 pm, Nirmal Kumar <nirmal.h...@gmail.com> wrote:
> Hi All,
>
> Can anyone explain the following Method Overriding Rules in Java:
>
> The access level *cannot be more restrictive* than the overridden method's
> access level.
> However the access level *can be less restrictive* than the overridden
> method's access level.
>
> The overridden method should not throw checked exceptions that are new or
> broader than the ones declared by the overridden method.
> The overriding method can throw narrower or fewer exceptions than the
> overridden method.
>
> Please give an example if possible.
>
> Thanks,
> Nirmal
>
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