Ed Watkeys wrote:
>
> On Wed, 9 Jun 1999, Raimee Stevens wrote:
>
> > This is a RE-POST since I haven't had any response.
>
> 1. The fact that no one replied to your message the first time should
> indicate to you that maybe you should try to rephrase your question.
>
> 2. I read your message the first time but couldn't figure out what you
> were doing. Specifically, how are you passing the vector from a
> servlet to an applet? It sounds vaguely like you're printing the
> vector to an output stream, and you're getting the string
> representation. Unless you're using RMI, object serialization, or
> something similar, you can't just "pass" a vector from a servlet to an
> applet.
OK,
First, thanks Mathew for your suggestion. I don't know if your code
compiles but it looked good. And you're right, my question isn't JServ
related per se, it was a Java coding question. However, I had no
nowhere else to turn (hmmm.)
Ed, exactly. I am "printing the
vector to an output stream, and getting the string representation."
Ill try to be more precise with my question next time. But since Java
is new to me, I wasn't sure what to ask. I was so close...I'll be
brief:
/* *****************************************
* r e a d s e r v l e t D a t a V e c t o r ( )
* This method receives a serialized vector of String Objects
* from a Servlet. I was initializing the servletDataVector with 1
Element.
* That's why I had only one line in my applet lstBox.
*/
public Vector readservletDataVector(ObjectInputStream
theInputFromServlet)
{
Vector theservletDataVector = new Vector();
try
{
// read the serialized vector String Objects
// **This was the problem:
//theservletDataVector.addElement(theInputFromServlet.readObject().toStirng());
//This is how I fixed it:
theservletDataVector = (Vector)
theInputFromServlet.readObject();
//Close the connection
theInputFromServlet.close();
}
catch (IOException e)
{
log(e.toString());
}
catch (Exception e)
{
System.out.println(e);
}
return theservletDataVector;
}
Thanks again.
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