I'm trying to figure out why idf is multiplied twice into the score of a term query. It sort of makes sense if you have just one term... the original weight is idf*boost, and the normalization factor is 1/(idf*boost), so you multiply in the idf again if you want the final score to contain an idf factor (instead of being normalized to 1.0).
But when you have a boolean query of two term queries, the amount of score each term contributes will vary with the square of their idfs, not their idfs. Is this what's intended? If so, the scoring formula one normally sees (tf*idf*boost*lengthNorm), doesn't seem to convey this fact. -Yonik Now hiring -- http://tinyurl.com/7m67g
