Hello,
This seams to be a similar solution like:
Term t = new Term(fieldname, term);
int count = searcher.docFreq(t);
The problem is, that in this situation it is not possible to apply a
filter object. If I don't wanna use this filter object, I would have
to use a complex search query, wich is - again - very slow. So,
unfortunatelly, your solution does not help.
Mathias
2009/9/15 Simon Willnauer <simon.willna...@googlemail.com>:
> Did you try:
> int numDocs
> TermDocs termDocs = reader.termDocs(new Term("myField", "myTerm"));
> while (termDocs.next()) { numDocs++; }
>
> simon
>
> On Tue, Sep 15, 2009 at 2:19 PM, Mathias Bank <mathias.b...@gmail.com> wrote:
>> Hello,
>>
>> I'm trying to find the number of documents for a specific term to
>> create text statistics. I'm not interested in ordering the results or
>> even recieving the first result. I just need the number of results.
>>
>> Currently, I'm trying to do this by using the lucene searcher class:
>>
>> IndexSearcher searcher = new IndexSearcher(reader);
>> String queryString = fieldname+":" + term;
>> QueryParser parser = new QueryParser(fieldname, new GermanAnalyzer());
>> TopDocs d = searcher.search(parser.parse(queryString), filter, 1);
>> int count = d.totalHits;
>>
>> The problem is, that there is a large index (optimized) with > 8 mio.
>> entries. One search could return a large number of search results (> 1
>> mio). Currently these search tasks take more than 15 secunds.
>>
>> The question is: is there any way to get the number of search results
>> faster? I think, that it could be optimized by not using a Weight
>> object (order is not interesting), but I haven't seen a way to do
>> this.
>>
>> I hope, someone has already solved this problem.
>>
>> Mathias
>>
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