Re: Fastest way to get number of matching documents

[Philippe]

Hi Paul,

thanks for the code. It is much faster than the implementation before.

Cheers,
    Philippe

Am 26.07.2010 16:25, schrieb Paul Libbrecht:

Le 26-juil.-10 à 16:01, Michael McCandless a écrit :

You can make a custom Collector?  Ie, it'd just increment a counter
for each hit.

As long as it does not call the Scorer.score() method then no scoring is done.

I've done that.
Code below.

It feels a bit stupid to have to do that though. Sounds like a normal thing that should have been done already.

paul

On Mon, Jul 26, 2010 at 9:18 AM, Philippe <mailer.tho...@gmail.com> wrote:

Hi,

for some queries I'm only interested in the number of matching documents. Is there a better/faster way to perform such a query, instead of retrieving all

TopDocs and counting the number of totalHits [1]?
And is it possible/worthwhile to "deactivate" ranking?

Cheers,
   Philippe

[1]
       TopDocs td= is.search(query, is.maxDoc());
       int result= td.totalHits;

public class CounterHitCollector extends HitCollector {

    private int count=0;

    public void collect(int doc, float score) {
        count++;
    }

    public int getCount() {
        return count;
    }
}


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