Thanks David, The first time I must have read it without paying the required attention. Do you know any trick or maybe a resource to another algorithm because I want to detect even if the point is exactly on the boundary.
Thanks. Mat�as Rodriguez. > From http://java.sun.com/j2se/1.4/docs/api/java/awt/Shape.html > > Definition of insideness: A point is considered to lie inside a Shape if > and only if: > > + it lies completely inside theShape boundary or > + it lies exactly on the Shape boundary and the space immediately > adjacent to the point in the increasing X direction is entirely > inside the boundary or > + it lies exactly on a horizontal boundary segment and the space > immediately adjacent to the point in the increasing Y direction > is inside the boundary. > > All three cases fail for (1,1). > > -David > > ------------------------+--------------------------+ > David Eisner | E-mail: [EMAIL PROTECTED] | > CALCE EPSC | Phone: 301-405-5341 | > University of Maryland | Fax: 301-314-9269 | > ------------------------+--------------------------+ > =========================================================================== To unsubscribe, send email to [EMAIL PROTECTED] and include in the body of the message "signoff JAVA2D-INTEREST". For general help, send email to [EMAIL PROTECTED] and include in the body of the message "help".
