If you aren't keen to follow the article try this:
import java.lang.reflect.*;
import java.util.*;
public class GenericTest
{
public HashMap<String,String> map1 = new HashMap<String,String>();
public HashMap<Date,Date> map2 = new HashMap<Date,Date>();
public static String fieldSignature(Object obj, String fieldName)
throws SecurityException,
NoSuchFieldException
{
StringBuffer signature = new StringBuffer(fieldName);
Field field = GenericTest.class.getField(fieldName);
Type genericFieldType = field.getGenericType();
if(genericFieldType instanceof ParameterizedType)
{
signature.append(" is of type
").append(obj.getClass().getName()).append("<");
ParameterizedType aType = (ParameterizedType)
genericFieldType;
Type[] fieldArgTypes = aType.getActualTypeArguments();
for(Type fieldArgType : fieldArgTypes)
{
Class fieldArgClass = (Class) fieldArgType;
signature.append(fieldArgClass.getName()).append(",");
}
signature.append(">");
}
return signature.toString();
}
public static void main(String[] args) throws SecurityException,
NoSuchFieldException
{
GenericTest test = new GenericTest();
System.out.println("map1.getClass() == map2.getClass() is "
+ (test.map1.getClass() == test.map2.getClass()) );
System.out.println("map1.getClass() is " +
test.map1.getClass());
System.out.println("map2.getClass() is " +
test.map2.getClass());
System.out.println(GenericTest.fieldSignature(test.map1,
"map1"));
System.out.println(GenericTest.fieldSignature(test.map2,
"map2"));
}
}
My quick test shows:
map1.getClass() == map2.getClass() is true
map1.getClass() is class java.util.HashMap
map2.getClass() is class java.util.HashMap
map1 is of type java.util.HashMap<java.lang.String,java.lang.String,>
map2 is of type java.util.HashMap<java.util.Date,java.util.Date,>
:-D
Tasos
On Nov 10, 12:46 pm, Tasos Zervos <[EMAIL PROTECTED]> wrote:
> The equality test has to return true otherwise you would be breaking
> compatibility with older code.
> This doesn't mean that there aren't other ways to find the "signature"
> of map1 and map2.
>
> The Reflection API does provide access to the "specific" types of
> generic signatures.
>
> Have a look at this 2005
> article:http://www-128.ibm.com/developerworks/java/library/j-cwt11085.html#h2
>
> The article series uses ASM (DRY) also later on.
>
> On Nov 4, 11:05 pm, Christian Catchpole <[EMAIL PROTECTED]>
> wrote:
>
> > Here is my analysis of the situation. I could be wrong. But here
> > goes..
>
> > When I got my copy of Java 5 my first question was, do generics really
> > take the cast out of the equation? I disassembled the code to find
> > the cast still exists. This implies that when you compile this..
>
> > HashMap<String,String> map = new HashMap<String,String>()
> > String string = map.get("");
>
> > The generated code actually equates to this..
>
> > HashMap map = new HashMap()
> > String string = (String)map.get("");
>
> > The class returned by map.getClass() does not know the map only
> > contains Strings. It's actually the reference to the map which
> > marshals the types.
>
> > I did a quick test...
>
> > HashMap<String,String> map1 = new HashMap<String,String>();
> > HashMap<Date,Date> map2 = new HashMap<Date,Date>();
>
> > System.out.println(map1.getClass() == map2.getClass());
>
> > true
>
> > They use the same class and can't therefore hold the type information
> > for both declarations.
>
> > I can only assume this re-compiler the posse were talking about, scans
> > the code for the actual cast / type check to determine the types.
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