On Fri, Feb 28, 2014 at 9:43 AM, clay <[email protected]> wrote:
> > > "Java's lambda approach is unique. It is more concise than scala's (due > to not needing to mention the types of the variables)," > > This doesn't sound correct. Scala offers type inference of lambda > parameters: > > val l = List(1,2,3) > l.fold(0)((a,b) => a+b) > You can go one step further: scala> l.fold(0)(_ + _) res0: Int = 6 -- Cédric -- You received this message because you are subscribed to the Google Groups "Java Posse" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/javaposse. For more options, visit https://groups.google.com/groups/opt_out.
