I know if I setup the two string variables as global variables, it
would worked too. But it doesn't seem right doing it like that.
On Sep 5, 8:20 pm, Norman Ho <[EMAIL PROTECTED]> wrote:
> If I set it up as a function, how do I get the method to return the
> two strings?
>
> On Sep 5, 8:00 pm, miga <[EMAIL PROTECTED]> wrote:
>
>
>
> > On Sep 5, 11:14 am, Norman Ho <[EMAIL PROTECTED]> wrote:
>
> > > Hi,
> > > I am just doing some recap on what I have study so far, and I try this
> > > codes to swap two strings, and it doesn't work. As I learnt, "String"
> > > type is not a primitive type, so when being passed to a method, it
> > > should be passed by reference, but when it comes back from the swap
> > > method, the strings are still the same. How can I make the swap to
> > > work?
>
> > > public static void main(String[] args) {
>
> > > String a = "aaa", b = "bbb";
> > > System.out.println("Before swap "
> > > + "a = " + a
> > > + " b = " + b);
> > > swap(a, b);
> > > System.out.println("After swap "
> > > + "a = " + a
> > > + " b = " + b);
> > > }
>
> > The problem is that the variables are local the functions, so that
> > their changes are not seen outside the function.
> > I think the solution would be to pass an array of those strings, swap
> > them, just similar as you did, then return the new array, so no void.
> > Then you will put the returned array in another empty new one in the
> > main method, and you retrieve the x and y strings.
> > Or you swap directly in the main (question of scope of the
> > references).
>
> > > static void swap(String x, String y){
> > > String temp = x;
> > > x = y;
> > > y = temp;
> > > }
>
> > > norman.
>
> > See also this thread: <http://forums.sun.com/thread.jspa?
> > threadID=638652&messageID=3739675>- Hide quoted text -
>
> > - Show quoted text -- Hide quoted text -
>
> - Show quoted text -
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