String longestname;
longestname=(lengthofname1>lengthofname2)?name1:name2;
longestname=(longestname>lengthofname3)?longestname:name3;
System.out.println(longestname + " has the longest first name!");
Hope I helped.
Regards,
Manu.
On Fri, Sep 19, 2008 at 3:14 PM, Rene Erwee <[EMAIL PROTECTED]> wrote:
> Hi all
>
>
>
> Thank you David for your good explanation of String Arrays which finally
> enabled me to finish the homework. However, I am wondering if there is a
> more condensed version to find and print the longest name. I can imagine
> If-else-else if statements will not work too well when one has a whole lot
> of names to compare.
>
>
>
> // Print the longest name
>
> if((lengthOfFirstNameOfPerson1>=lengthOfFirstNameOfPerson2) &&
>
> (lengthOfFirstNameOfPerson1>=lengthOfFirstNameOfPerson3)){
>
> System.out.println(firstNameOfPerson1[0] + " has the longest
> first name");
>
> }
>
> else if ((lengthOfFirstNameOfPerson2>=lengthOfFirstNameOfPerson1)
> &&
>
> (lengthOfFirstNameOfPerson2>=lengthOfFirstNameOfPerson3)){
>
> System.out.println(firstNameOfPerson2[0] + " has the longest
> first name");
>
> }
>
> else {
>
> System.out.println(firstNameOfPerson3[0] + " has the longest
> first name");
>
> }
>
> }
>
> }
>
>
>
> Thanks
>
> * *
>
> *Rene Erwee*
>
> >
>
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