On Mar 5, 4:20 pm, Tanya Dina Ruttenberg <[email protected]>
wrote:
> Why do you get an "already been caught" exception when you place
> MyChildException before MyParentException? The exercise doesn't explain why
> you get this.try { throw new MyChildException();} catch
> (MyParentException e) { System.err.println("Caught
> MyParentException");} catch (MyChildException e) { // Compile error
> expected System.err.println("Caught MyChildtException");}
> TDR
See the pre-reading material, (study the graphics and comments):
http://java.sun.com/docs/books/tutorial/essential/exceptions/definition.html
and take into account that ChildException extends ParentException.
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