Thanks (both of you), makes sense now!
On Fri, Jun 26, 2009 at 7:57 PM, Babu Rajendran <[email protected]>wrote:
> Hi Bryan,
>
> In the first case
> System.out.print("New name: " + generateNewName(args));
> the method print() from the PrintWriter class which accepts a String
> argument is called. Since you are concatenating your character array which
> is returned by generateNewName(args) with a String "New name: ", the
> toString() method is called on the character array to convert it to a String
> as well so that concatenation can occur. But calling toString() on the array
> causes the memory reference to be printed.
>
> In the second case
> System.out.print(generateNewName(args));
> the method print() from the PrintWriter class which accepts a character
> array as an argument is called. So it prints correctly.
>
> To make your first case print the output correctly instead of the memory
> reference, use the valueOf method from the String class. Your code should be
>
> System.out.print("New name: " + String.valueOf(generateNewName(args)));
>
> Hope it makes sense. Kindly refer the JavaDoc too.
>
> Thanks & Regards,
> Babu Rajendran
>
>
> On Sat, Jun 27, 2009 at 1:11 AM, Bryan <[email protected]> wrote:
>
>>
>> I am attempting to get my generate new name project to output the name
>> it creates. My generateNewName method outputs the new name as a char
>> array.
>> Behold two lines of code-
>> System.out.print("New name: " + generateNewName(args));
>> System.out.print(generateNewName(args));
>>
>> The former outputs "New name: [...@3e25a5"
>> The latter outputs the actual name (in this case, lola).
>>
>> Why do these (which both appear to call the same method with the same
>> parameters) output different results? I assume that the former is a
>> memory reference. How do I make it work (better)?
>>
>> Thanks!
>>
>> >>
>>
>
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