On Jun 29, 1:19 pm, Bong <[email protected]> wrote:
> int[][][] myInt = new int[2][2][2];
> int myNum1 = 1000;
>
> for (int i = 0; i < myInt.length; i++) {
> for (int j = 0; j < myInt[i].length; j++) {
> for (int k = 0; k < myInt[i][j].length; k++) {
> myNum1 = myNum1 + i + j + k;
When you add i+j+k to myNum1 you cause a hole in the indexes.
A three dimensionnal array is just an array of two dinmensional array,
and the same for a n-dimensionnal array.
Hence your loop are the same for every dimension, except that in the
most inner one, you should add 1 to the num.
So:
myNum1 = myNum1+1;
Proof of concept:
i = 0
j = 0
k = 0
myNum1 = 1001
i = 0
j = 0
k = 1
myNum1 = 1002
i = 0
j = 1
k = 0
myNum1 = 1003
...
(first loop on k, then on j (and innerly on k), then on i (and innerly
on j, in turn innerly on k)
See you have to change the initial value of myNum1 to begin with 1000.
Hope this helps.
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