hiii, Thankyou verymuch for your help.I got my program work.with your help.
On Sat, Aug 8, 2009 at 12:51 PM, pacior<[email protected]> wrote: > > Sorry, that I made a mistake on topics. > Here, i think, program is rather fine. > You have to write all the names from input to the output too. > In other words, You have here to system.out an args array. > > You bether think about "dividing presentation from logic", which > means, that > You don't use System.out.println in generateNewName method - instead > of this, You write a method > String generateNewName, which returns string containing newname. > You can always build string from char array: > char[] arr = new char[args.length]; > ... > String s = new String(arr); > > Dividing logic from presentation is shown in later courses ( i am > talking of course about MVC pattern ) > > Regards > Grzegorz Patynek > On Aug 8, 7:24 pm, devika shukla <[email protected]> wrote: >> Hi all. >> i need your help in this program,in which i have to get the newname >> which comprises of the second alphabet of each of the name passed >> through command line arguments. >> the code that I tried out is given below >> >> public class builtinclasses { >> >> /** >> * @param args the command line arguments >> */ >> public static void main(String[] args) { >> >> if(args.length==0) >> System.exit(0); >> for(int i=0;i<args.length;i++){ >> System.out.println(args[i]); >> } >> System.out.println("New name is: "); >> generateNewName(args); >> } >> >> // TODO code application logic here >> public static void generateNewName(String[] args) >> { >> for (int i=0;i<args.length;i++) >> { >> System.out.print(args[i].charAt(1)); >> } >> } >> } >> >> please help me to modify this code to get the desired result. >> Thanks and Regards > > > > --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/javaprogrammingwithpassion?hl=en -~----------~----~----~----~------~----~------~--~---
