Le 8 avr. 10 à 03:50, Kim Ching Koh a écrit :
Hi,
Thanks.. I managed to write the code to compare three persons, below
is my code, but I am just thinking how to use a two dimensional
array for the nameArrayForPerson, instead of three arrays. The key
here is still to let .split() define the array size for the
nameArray. Any tips?
Regards
KC
public static void main(String[] args) {
// TODO code application logic here
String fullName[] = new String[3];
String longestFirstName = "";
for (int i = 0; i < fullName.length; i++) {
fullName[i] = JOptionPane.showInputDialog("Please enter
a family member's name " + i + 1);
System.out.println(fullName[i]);
}
...deleted to not show your whole homework solution
}
Instead of working on retrieving the longest first name out side of
the for loop, you may initialize before the for loop a String
firstName to an empty string and then use the split method on the
fullName[i] you read inside the for loop. Then you compare the
longestFirstName with the firstName, always inside the for loop, and
change the former to the latter if needed. You also need an index
(initialized before the loop, and changed inside the loop) to retrieve
after the loop the index which corresponds to the longest first name.
There may be other solutions.
Michèle
On Wed, Apr 7, 2010 at 10:16 PM, miga <[email protected]> wrote:
On Apr 7, 2:51 pm, kc <[email protected]> wrote:
> Hi,
>
> Is there a typo error here? To compare Two or Three family members?
No there is no error. You compare the first name of three members of
the same family. It may happen that two member of this family have
first name which length is the same and both have the longest name in
the family, like Pat, John and Duke, John and Dude have both the
longest name, 4 characters for both. The tie refers to this, so if it
is the case, you display the one you want, either John or Duke.
Hope it helps,
Michèle
>
> Ask the English version of the full names (first-name last-name) of
> three of your family members using showInputDialog() method of the
> JOptionPane class.
> Display the name of the family member who has the longest first name
> (not the longest of the total name) as following. (If there is a
> tie, just display one of the two.)
>
> Regards
> KC
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