Hello Guys,

I really appreciate your responses, Thanks Alfor for introducing me to some
new methods as I really appreciate it. Also Mihai, you have been there
before now and I will say thanks to you again but why is it that I must
initialize before using the String ans? because going by your solution, I
must still have to initialize the String for it to work.

Thanks G for the Naming Convention thing as it will also go a long way.

Regards
On Wed, Sep 1, 2010 at 9:47 PM, Mihai DINCA <[email protected]> wrote:

>  Hi
>
> You say "String and, ans;", then, later, "and = name.charAt(i);".
>
> As the error message says, the method "charAt(...)" returns a value of type
> "char", while your variable "and" is of type "String".
>
> There are many ways to make your code working, but the simplest way is to
> replace the line of code:
>     ...
>     String and, ans;
>     ...
> by two lines:
>     ...
>     String ans;
>     *char and;*
>     ...
>
> The line of code "ans = ans + and;" will still work after this
> modification, as the "+" operator allows to append a char (or any other
> simple type) to a String (this is what allows you to write "for(int i = 0;
> i < 10; i++) System.out.println(*"Iteration # " + i*);").
>
> Hope it helps
> Mihai
>
>
> Le 01/09/2010 22:10, Olukosi, Olanrewaju Temitope a écrit :
>
> Hello Guys,
>
> I am having some problems running this program. Kindly help
>
> import java.util.Scanner;
> class backward
> {
>     public static void main (String[] Args)
>     {
>         Scanner in=new Scanner(System.in);
>         System.out.print("Enter a Name to Reverse:");
>         String name = in.nextLine();
>         String and, ans;
>         int l=name.length();
>         int i;
>         for (i=l-1; i>=0; i--)
>         {
>             and=name.charAt(i);
>             ans= ans+and;
>         }
>         System.out.println("The Output is:" + ans);
>     }
> }
>
>
> The error I have is stated thus using TextPad
>
> C:\JavaClass\backward.java:14: incompatible types
> found   : char
> required: java.lang.String
>             and=name.charAt(i);
>                            ^
> 1 error
>
> Tool completed with exit code 1
>
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-- 
DISCLAIMER
This message contains privileged and confidential information and is
intended only for the individual named. If you are not the intended
recipient you should not disseminate, distribute, store, print, copy or
deliver this message. Please notify the sender immediately by e-mail if you
have received this e-mail by mistake and delete this e-mail and any
attachments from your system. E-mail transmission cannot be guaranteed to be
secure or error-free as information could be intercepted, corrupted, lost,
destroyed, arrive late or incomplete or contain viruses. The sender
therefore does not accept liability for any errors or omissions in the
contents of this message which arise as a result of e-mail transmission.
Thank you   --   Tope Olukosi

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