Hi Pravglad, Check this code:
package myownjavaarrayproject;
import javax.swing.JOptionPane;
/**
*
* @author root
*/
public class Main {
/**
* @param args the command line arguments
*/
public static void main(String[] args) {
// TODO code application logic here
String askFor[]={"First Name","Last Name"};
int max=0;
int maxFirstName=0;
String family[][]=new String[3][2]; //Here we store the first
name and last name
for(int i=0;i< family.length;i++){
// Getting the First and Last Name of three family members
for(int j=0;j<family[i].length;j++){
if(j==0){ // if j=0, we are asking for the first name,
else, the last name.
family[i][j]=JOptionPane.showInputDialog("Enter a
"+askFor[j]+" of your family member number "+(i+1)+":");
}else{
family[i][j]=JOptionPane.showInputDialog("Enter a
"+askFor[j]+" of your family member "+(i+1)+":");
}
}
System.out.println(family[i][0]+ " "+ family[i][1]+" has
"+family[i][0].length()+ " characters in the First Name ");
}// End for
// Checking what Family Member has the longest First Name
for(int k=0;k<family.length;k++){
if(family[k][0].length()>max){
maxFirstName=k;
max=family[k][0].length();
}
}
// Displaying the result
String message=family[maxFirstName][0] +"
"+family[maxFirstName][1] + " has the longer first name, with ";
message=message+" "+family[maxFirstName][0].length()+ "
characters.";
System.out.println("+-----------------+");
System.out.println(message);
JOptionPane.showMessageDialog(null, message);
}
}
On Oct 11, 1:02 pm, Mihai DINCA <[email protected]> wrote:
> Hi Pravglad
>
> I'm OK with the first part. I would write it in less code, such as:
> ...
> String firstPerson = JOptionPane.showInputDialog( ... );
> String secondPerson = JOptionPane.showInputDialog( ... );
> ...
> String[ ] firstPersonName = firstPerson.split(" ");
> ...
> but it works perfectly in the way you did.
>
> Then, for the second part, the path you took is very complicated, I can
> hardly follow. In the big lines (assuming that len1, len2 and len3 are
> the lengths of the Strings respectively), you wrote:
>
> // First check :
> // -----------------
> if len1 > len2 then {
> if len3 > len1 then print "The third person wins" .
>
> }
>
> // Second check (an independent one) :
> // ----------------------------------------------------
> if len1 == len2 then {
> print "First equals Second"} else {
>
> if len2 > len3 then {
> print "Second wins"
> } else print "First wins"
>
> }
>
> There are many ways to improve. One would be to presume that the first
> person may be the winner. But if the second has longer name, then the
> second might be the winner. But if the third is longer then the second
> third is the winner. Something like:
>
> // We assume that the first is the winner
> if len1 < len2 then { // The first cannot be the winner, but the
> second can
> if len2 < len3 then // The second cannot be the winner neither
> print "Three wins"
> else
> print "Two wins"
> } else { // The first still can be the winner
> if len1 < len3 then // The third is bigger than 1 that is
> bigger or equal to 2
> print "Three wins"
> else
> print "First wins"
> }
>
> Now, try to write this in Java instead of "pseudo code". Just one more
> suggestion: in complicated comparisons like this, try to keep the "<" or
> ">" signs in the same direction (i.e. either use only "<"s or use only
> ">"s), otherwise it is difficult to follow.
>
> Hope it helps
> Mihai
>
> Le 11/10/2010 07:24, Pravglad a �crit :
>
>
>
> > i cant seem to get this to wrong.. one or the other goes wrong..can
> > someone tlel me whats worng with this code
>
> > Display the name of the family member who has the longest first name
> > (not the longest of the total name) as following. (If there is a
> > tie, just display one of the two.)
>
> > */
> > import javax.swing.*;
>
> > public class MyJavaArray {
>
> > public static void main(String[] args) {
>
> > // Step 1
> > String firstPerson;
> > String secondPerson;
> > String thirdPerson;
>
> > // Step 2
> > firstPerson = JOptionPane.showInputDialog("Please enter your
> > name");
> > secondPerson = JOptionPane.showInputDialog("Please enter your
> > name");
> > thirdPerson = JOptionPane.showInputDialog("Please enter your
> > name");
>
> > //Step 3
> > // creating the two arrays
> > String[] firstPersonName = new String[2];
> > String[] secondPersonName = new String[2];
> > String[] thirdPersonName = new String[2];
> > // splitting the two names into the newly created array
> > firstPersonName = firstPerson.split(" ");
> > secondPersonName = secondPerson.split(" ");
> > thirdPersonName = thirdPerson.split(" ");
>
> > // Step 4
> > if (firstPersonName[0].length()>
> > secondPersonName[0].length() )
> > if (firstPersonName[0].length()<
> > thirdPersonName[0].length()) {
> > System.out.println(thirdPersonName[0] + " has longer
> > first name than " + secondPersonName[0] + " and " +
> > firstPersonName[0]);
>
> > } if (firstPersonName[0].length() ==
> > secondPersonName[0].length()) {
> > System.out.println(secondPersonName[0] + "'s first name
> > is the same length as " + firstPersonName[0] + "'s first name.");
> > } else if (firstPersonName[0].length() ==
> > thirdPersonName[0].length()) {
> > System.out.println(thirdPersonName[0] + "'s first name
> > is the same length as " + firstPersonName[0] + "'s first name.");
> > } else if (secondPersonName[0].length()>
> > thirdPersonName[0].length()) {
> > System.out.println(secondPersonName[0] + " has longer
> > first name than " + thirdPersonName[0] + " and " +
> > firstPersonName[0]);
> > } else
> > System.out.println(firstPersonName[0] + " has longer
> > name than " + secondPersonName[0] + " and " + thirdPersonName[0]);
>
> > }
> > }
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