Pasquale Imbemba [http://community.jboss.org/people/pi4630] created the 
discussion

"TimerBean: Only one @Timeout on SLSB?"

To view the discussion, visit: http://community.jboss.org/message/627369#627369

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I've two private methdos on my SLSB, say A and B.
Both methods are annotated with @Timeout, return void, and take Timer as an 
argument.

Two public methods implemented by the interface are basically doing the same 
thing: according to which one has been called, the create a TimerInfo instance 
(a container class [POJO] that implements java.io.Serializable, carrying a 
"label" and an "element", both String), set this instance as Info when creating 
the timer. Of course, before I create one, I lookup if a timer with that label 
and that element already exists.

My client invokes the exposed method that should finish in having method A 
invoked.

I then set two breakpoints, one at the beginning of A, the other at the 
beginning of B.

When I debug my SLSB with a timer created with timerInfo set so that method A 
should be invoked, the breakpoint in A never gets active, but it the one in B! 
Of course, at the beginning of these private methods I check which timer is 
calling me and therefore do not execute the logic.

A workaround could be using @Timeout only on *one* method, and then call the A 
or B according to the TimerInfo set, sort of "deviator" method.

I enclose the sourcecode of my SLSB... I wonder what I've missed or completely 
got wrong about Timers.


Thanks
~pasquale
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