I don't know what exactly you mean with "without mapping that to the database",
but anyway I have solved something similar as follows:
| @Entity
| @Table(name = "person", uniqueConstraints = @UniqueConstraint(columnNames =
{"firstname", "lastname"}))
| public class Person {
| @Id
| private Long id;
| @Column(name = "firstname")
| private String firstName;
| @Column(name = "lastname")
| private String lastName;
| private String address;
|
| public Long getId() {
| return id;
| }
|
| public void setId(Long id) {
| this.id = id;
| }
|
| public String getFirstName() {
| return firstName;
| }
|
| public void setFirstName(String firstName) {
| this.firstName = firstName;
| }
|
| public String getLastName() {
| return lastName;
| }
|
| public void setLastName(String lastName) {
| this.lastName = lastName;
| }
|
| public String getAddress() {
| return address;
| }
|
| public void setAddress(String address) {
| this.address = address;
| }
| }
|
|
With above, the validation is done in database layer, but it is caught by JPA
and it throws a javax.persistence.EntityExistsException. It works for me in the
sense I don't have to write any special login in a Session Bean to validate
this.
HTH.
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