Hello Paul,
Thanks for taking my questions. I am using jdb that comes with jsdk1.4.2
Here are some more details about what shows up:
Here are my two classes:
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dev_root/src/org/me/b/B.java:
package org.me.b;
import org.me.a.A;
public class B extends A{
public static void main(String arg[]){
B b=new B();
System.out.println(""+b.i);
}
}
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dev_root/src/org/me/a/A.java:
package org.me.a;
import java.util.regex.*;
public class A{
public int i=1;
public int j=1;
public int k=1;
public int l=1;
public Pattern p = Pattern.compile("a*b");
}
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I have set my source path to dev_root/src
and I have set my run directory to dev_root
I open B.java and press C-c C-v C-d
And another buffer is opened splitting my window with the following <<EOF
cd dev_root
jdb -launch org.me.b.B (I have orgmeb.jar in my classpath)
Set uncaught java.lang.Throwable
Set deferred uncaught java.lang.Throwable
Initializing jdb ...
> step
Nothing suspended.
>
VM Started: No frames on the current call stack
main[1]
EOF
The cursor is set to > step (on the s)
I just press return to step, then after two more steps,
the jdb buffer split window is replaced by A.java!
>From there I have C-c C-a C-o to step up and return to B.java.
But now my debugger window is gone,
so I have to C-x o to go to A.java (since the focus was put back into
B.java) and
C-x b to get back the debug buffer from where I can step again.
It seems more natural to have the debug buffer always visible and
have the "code" split window do the correct switching between source files.
Am I doing something wrong?
is there a better way of running the debugger that I don't know about?
Thanks,
-frankie
