Try Perl...
This example processes all the files in the directory:
$dirname = shift @ARGV;
opendir(DIR, $dirname) or die "can not open $dirname : $!\n";
while( defined ($filename = readdir DIR) ) {
#$filename = shift @ARGV;
print "$dirname/$filename\n";
if($filename ne "." && $filename ne "..") {
open(INPUTFILE, "< $dirname/$filename") or die "can not open
$dirname/$filename : $!\n";
while(<INPUTFILE>) {
#DO SOMETHING WITH THE FILE'S CONTENTS....
}
}
}
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
Sent: Friday, May 10, 2002 9:39 AM
To: JDJList
Subject: [jdjlist] get the names of all the file under a folder
Hi all,
Does anybody know how to get the names of all the files under a folder? I
assume we should be able to create an Iterator of the names using some
Class.
Any experience about it?
Thanks and have a great weekend!
TongHua
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