How do u validate your xml file against DTD or Schema withour using XML
parser?.For generating XML file you no need to have a parser.
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"saurabh"
<skedia@itil. To: "JDJList"
<[EMAIL PROTECTED]>
com> cc:
Subject: [jdjlist] Xml generation
2002/05/23
16:12
Please
respond to
"JDJList"
Hi all,
I have used a strange approach to generating XML based on data retrieved
from database and have consequently displayed it in HTML format using XSL
here is the code ihave used:
Properties pEnv = new Properties();
pEnv.load(new FileInputStream("C:
\\jboss-2.4\\tomcat\\webapps\\ROOT\\jspxml\\abc.dtd"));//loaded my DTD file
in same directory where my XML file will be generated
try{
*****Creating a string that looks like XML*****
String xmlG="<?xml version=\"1.0\" ?>\n";
xmlG=xmlG+"<!DOCTYPE abc >\n\n";
xmlG=xmlG+"<abc>\n";
v5=remote1.getEmployeeNames();//fetching data from database and writng it
as part of string using EJB method call
for(int i=0;i<v5.size();i++)
{
vRow=new Vector();
vRow=(Vector)v5.elementAt(i);
xmlG=xmlG+"<people>\n"+
"<person>\n"+
"<name>\n"+
"<firstname>"+(String)vRow.get(1)+"</firstname>\n"+
"<lastname>"+(String)vRow.get(2)+"</lastname>\n"+
"<ecn>"+(String)vRow.get(0)+"</ecn>\n"+
"</name>\n"+
"</person>\n"+
"</people>";
}
xmlG=xmlG+"</abc>";
******making a xml file using the String*****
FileOutputStream f= new FileOutputStream
("C:/jboss-2.4/tomcat/webapps/ROOT/jspxml/myxml.xml");
DataOutputStream d= new DataOutputStream(f);
d.writeBytes(xmlG);
}catch(Exception ex)
{
out.println(" Exceptionin in exp.jsp: "+ex);
}
response.sendRedirect("bookdata.jsp");//here,the xml file generated
together with xsl(written separately) is being converted into html format
for display using Taglibs.
%>
I have not used any XML parser for the xml generation ...this works...I had
also written a DTD .
Is this the correct approach...what would the negative implications
be...can anyone comment..
thanks in advance,
Saurabh
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