Which works only if fullDouble < 2^31. Given that a double is 64 bits,
I'd use a long rather than an int. That will work for all doubles that
can exactly represent an integer (< 2^52).
=Spencer
Conway. Fintan (IT Solutions) wrote:
>How about :
>
>public double[] myModf(double fullDouble) {
> int intVal = (int)fullDouble;
> double remainder = fullDouble - intVal;
>
> double[] retVal = new double[2];
> retVal[0] = intVal;
> retVal[1] = remainder;
>
> return retVal;
>}
>
>HTH,
>
>Fintan
>
>
>
>
>>-----Original Message-----
>>From: Jeff Fisher [SMTP:[EMAIL PROTECTED]]
>>Sent: 04 September 2002 13:02
>>To: JDJList
>>Subject: [jdjlist] modf in in java
>>
>>Does java have anything like the modf c function? I checked the math
>>class,
>>but there is just ciel and floor. I can get the first part of the double
>>value by casting as to an int, but the fractional part is not so easy. I
>>can get it as a double, but I'd like it as an integer.
>>
>>So what I'm trying to do here is split the number 123.45 into 123 and 45.
>>
>>Any thoughts?
>>
>>Thanks
>>
>>Jeff
>>
>>To change your JDJList options, please visit:
>>http://www.sys-con.com/java/list.cfm
>>
>>
>
>
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