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Dividing by 10 makes it 0.
Paul Franz
----- Original Message -----
Sent: Thursday, September 05, 2002 10:58
AM
Subject: [jdjlist] Re: Getting digits
from an integer
what happens when number=1 on the final pass?
Paul Franz <[EMAIL PROTECTED]>wrote:
You
need to do the following:
while (number !=
0)
{
System.out.println ("digit = "+(number % 10));
number /=
10;
}
The >> is a binary shift operator.
Paul
Franz
----- Original Message -----
From: "Jeff Fisher"
<[EMAIL PROTECTED]>
To: "JDJList"
<[EMAIL PROTECTED]>
Sent: Wednesday, September 04, 2002 7:59
AM
Subject: [jdjlist] Getting digits from an integer
> I
need to be able to get each individual digit from an integer as an
>
integer. I think I should be able to do this by using the >>
operator,
but
> I just can't seem to figure it out.
>
>
For example if I have a number 123, I need to get 3, then the 2, then
the
1.
> It doesn't really matter the order, I just need the
digits. I suppose I
> could convert it to a string and go that route,
but that seems ! like a
waste.
>
> Does anyone have
experience with this or can point me to some
>
examples/information.
>
> Thanks
>
>
Jeff
>
> To change your JDJList options, please
visit:
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>
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