[jdjlist] Re: Double multiplication

[Paul Franz]

Hmm, that does look a little strange. I would think that the result would be 1.20000000001E-8 but that might be due to the String formatter. If you are asking why does 12.0 show up as 12.0000000001 that is easy to explain. It is due to the binary representation of a decimal number.   Paul Franz ----- Original Message ----- From: Ivan Bradac To: JDJList Sent: Thursday, September 19, 2002 10:31 AM Subject: [jdjlist] Double multiplication Hi   I have written a sample test program: .........   public static void main (String args[])      {         Double             op1 = new Double(12.0),             op2 = new Double(1E-9),             res = new Double ( op1.doubleValue()*op2.doubleValue() );                 System.out.println("op1: " + op1);         System.out.println("op2: " + op2);         System.out.println("res: " + res);     } The output is:   op1: 12.0000000001 op2: 1.0E-9 res: 1.2000000000100001E-8 What the @!# is going on?   How can I fix this?   Any help appreciated.   Thanks   Ivan To change your JDJList options, please visit: http://www.sys-con.com/java/list.cfm To change your JDJList options, please visit: http://www.sys-con.com/java/list.cfm