You could create a file or create parse ( new org.xml.sax.InputSource( ByteArrayInputStream(xmlString.toCharArray() ) )) .
InputStream Regards, Kok Cheong > -----Original Message----- > From: Anurag Sikchi [SMTP:[EMAIL PROTECTED]] > Sent: Friday, October 18, 2002 8:05 PM > To: JDJList > Subject: [jdjlist] XML Parsing of an xml message string > > > I need to parse an xml string received as a string message. I am using the > xerces parser. Could somebody tell me how do to this. > The parser.parse() method in the api expects a file uri. However, I need > to pase an xml string and not a file. > > thanks, > Anurag > > ____________________________________________________ > To change your JDJList options, please visit: > http://www.sys-con.com/java/list.cfm > > Be respectful! Clean up your posts before replying > ____________________________________________________ ____________________________________________________ To change your JDJList options, please visit: http://www.sys-con.com/java/list.cfm Be respectful! Clean up your posts before replying ____________________________________________________
