May the problem be the Java's nature of the "OR" || which is "Exclusive OR", i.e.
a || b
means that if a is true, b is not evaluated. Maybe you're looking for "Inclusive OR" i.e. if a or b, both getting evaluated, which in Java is:
a | b
Although, frankly, I do not see much of a point for this here...
IMHO,
if( n <\<> 0)
=>
if(n < 0)
in Java will cover both conditions, as the number n can not be sulmonteniously less then 0 and equals to 0.
Yah? Or am I missing something?
Greg
-----Original Message-----
From: Spencer W. Thomas [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, November 26, 2002 2:13 PM
To: JDJList
Subject: [jdjlist] Re: In Java is this a valid expression (if( n <\<> 0
))
Arrgh. I meant to say "whenever n is NOT 0".
Spencer W. Thomas wrote:
>
>
> [EMAIL PROTECTED] wrote:
>
>> No. I'm assuming you are trying to say "if (n is less than or not
>> equal to 0)...."
>> You can try this instead:
>>
>> int n={some integer};
>>
>> if (n < 0 || n != 0)
>> System.out.println("foo happens here");
>> else
>> System.out.println("bar happens here");
>
>
> Try this. It will print "foo happens here" only when n is 0.
>
>>
>>
>> However, a clearer way to code it is this:
>>
>> if (n >= 0)
>> System.out.println("bar happens here");
>> else
>> System.out.println("foo happens here");
>> ____________________________________________________
>
>
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